A water skier is towing by motorboat at a constant velocity of magnitude 15 km /h. The boat speed up, and after a short interval the skier is towed at a new constant velocity of magnitude 20 km/h. What is the net force on the skier when she is moving at 15 km/h? And at 20 km/h?

The skier is experimenting a net force of 0 newtons in both cases. (, )

Explanation:

According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.

Therefore, the skier is experimenting a net force of 0 newtons in both cases.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

a. vertically

explanation:

i tried it and took the test

if im wrong then we have different tests