Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
How much energy, in Joules, was absorbed by the iron block? *

How much energy, in Joules, was absorbed by the copper block? *

Energy absorbed by Iron block E (iron) = 460.5 J

Energy absorbed by Copper block E (Copper) = 376.8 J

Explanation:

To find the heat absorbed, we can use the formula as,

q = m c ΔT

Here, Mass = m = 10 g = 0.01 kg

ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C

c = specific heat capacity

c for iron = 460.5 J/kg K

c for copper = 376.8 J/kg K

Plugin the values in the above equation, we will get,

q (iron) = 0.01 kg × 460.5 J/kg K × 100 K

            = 460.5 J

q (copper) = 0.01 kg ×  376.8 J/kg K × 100 K

                 = 376.8 J

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.