Compound W, C6H11Cl, undergoes base-promoted E2 elimination to form a single alkene Y. Under similar reaction conditions X, C6H11Br, affords Y and an isomeric alkene. Catalytic hydrogenation of Y produces methylcyclopentane. W readily undergoes an SN2 reaction with sodium iodide in acetone. X does not undergo a similar SN2 reaction. What are the structures of W and X

; The structures of both compounds are shown in the attached image.

Explanation:

First, compound W has the molecular formula C6H11Cl, it is observed that it does not have double bonds. removal of E2 produces compound Y, which is an alkene, which is hydrogenated and produces a methylcyclopentane.

Compound W is an alkyl halide that undergoes an SN1 reaction with sodium iodide in the presence of acetone forming the corresponding iodine compound.

while compound X is a tertiary alkyl halide, it is sterically restricted to undergo SN2 reactions.

linda: 3 ; laura: 15

step-by-step explanation:

note that linda + laura's age is 18, and that linda is 12 years younger than her sister.

let "linda" = x , "laura" = y:

x + y = 18

x = y - 12

first, plug in y - 12 for x in the first equation:

(y - 12) + y = 18

simplify.

2y - 12 = 18

isolate the variable (y). note the equal sign, what you do to one side, you do to the other. do the opposite of pemdas. first add, then divide.

2y - 12 (+12) = 18 (+12)

2y = 18 + 12

2y = 30

(2y)/2 = (30)/2

y = 30/2

y = 15

next, plug in 15 for y in the second equation (the other equation would work too).

x = y - 12

x = (15) - 12

x = 3

linda's age is 3, laura's age is 15.

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