If you have 35 ml of gas in a closed container under 1.23 atm of pressure, what will the volume be if the pressure increased to 3 atm

New volume is 14.35 mL

Explanation:

When a system of a gas keeps on constant its temperature and number of moles, the pressure is modified indirectly proportional to the volume:

Pressure increased → Volume decreased

Pressure decreased → Volume increased.

The relation you have to apply is: P₁ . V₁ = P₂. V₂

1.23 atm . 35 mL = 3 atm . V₂

(1.23 atm . 35 mL / 3 atm)  = V₂

V₂ = 14.35 mL

The new volume will be 14.35 mL

Explanation:

Step 1: Data given

Volume of the gas = 35 mL = 0.035 L

Pressure = 1.23 atm

The pressure increased to 3 atm

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.23 atm

⇒with V1 = the initial volume = 0.035 L

⇒with P2 = the increased pressure = 3.0 atm

⇒with V2 = the new volume

1.23 * 0.035 = 3.0 * V2

V2 = 0.01435 L = 14.35 mL

The new volume will be 14.35 mL

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.