Agas expands at a constant pressure of 3 atm from a volume of 0.02 cubic meters to 0.10 cubic meters. in the process it experiences an increase in internal energy of 3.0 × 105 joules. (note: 1 pa = 1n/m2 and 1 atm = 1.013 × 105 pa ) what is the work done by the gas? how much heat is absorbed by the gas? identify the thermodynamic process.

a)

For a gas transformation occuring at a constant pressure, the work done by the gas is given by

where

p is the gas pressure

V_f is the final volume of the gas

V_i is the initial volume

For the gas in the problem,

is the pressure

is the initial volume

is the final volume

Substituting,

b)

The heat absorbed by the gas can be found by using the 1st law of thermodynamics:

where

is the change in internal energy of the gas

Q is the heat absorbed

W is the work done

Here we have

So we can solve the equation to find Q:

And this process is an isobaric process (=at constant pressure).

this means that the temperature of both substances will be equal

momentum of soft ball three times less than baskey ball