How many moles of Al(CN)3 are in 227 g of the compound?

2.16 moles Al(CN)3

Explanation: To find the number of moles of Al( CN)3 we will use stoichiometry which is the relationship of mole with molar mass.

227 g Al(CN)3 x 1 mole Al(CN)3 / 105 g Al(CN)3

= 2.16 moles Al(CN)3

Cancel out the unit of grams Al(CN)3 and the remaining unit is in moles Al(CN)3.

i'm assuming that it's c.) red bank..