Chemistry, 13.03.2020 18:31 reycaden

What is the percent composition of the compound formed when 2.70 g of aluminum combines with oxygen to form 5.10 g of aluminum oxide? show your work

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Answer from: jphan19

The study of chemicals and bonds is called chemistry.

The correct % of oxygen = 47.1 % and % aluminium = 52.9 %

What is chemical composition?Chemical composition refers to the identity and number of the chemical elements that make up any particular compound.

All the data is given in the question as follows:-

Mass of aluminum = 2.70 grams Mass of aluminum oxide = 5.10 grams Balanced reaction 4Al + 3O_2 ----2Al_2O_3

According to the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.

Mass oxygen + mass aluminium = mass aluminium oxide

Mass oxygen + 2.70 grams = 5.10 grams Mass oxygen = 5.10 grams - 2.70 grams Mass oxygen = 2.40 grams

% oxygen = $\frac{mass \ oxygen}{mass\ aluminium \ oxide} * 100 %$

% oxygen = $\frac{2.40}{5.10 grams} * 100 %$

% oxygen = 47.1 %

For aluminium

% aluminium = $\frac{2.70}{5.10} * 100 %$

% aluminium = 52.9 %

The total percentage is 47.1 % + 52.9 % = 100 %.

For more information about the chemical composition, refer to the link:-

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Answer from: jeieiejej

% oxygen = 47.1 %

% aluminium = 52.9 %

Explanation:

Step 1: Data given

Mass of aluminium = 2.70 grams

Mass of aluminium oxide = 5.10 grams

Step 2: The balanced equation

4Al + 3O2 →2Al2O3

Step 3: Calculate mass of oxygen

The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.

Mass oxygen + mass aluminium = mass aluminium oxide

Mass oxygen + 2.70 grams = 5.10 grams

Mass oxygen = 5.10 grams - 2.70 grams

Mass oxygen = 2.40 grams

Step 4: Calculate percent composition

% oxygen = (mass oxygen / mass aluminium oxide) * 100 %

% oxygen = (2.40 grams / 5.10 grams ) * 100 %

% oxygen = 47.1 %

% aluminium = (mass aluminium / mass aluminium oxide)

% aluminium = (2.70 grams / 5.10 grams ) * 100 %

% aluminium = 52.9 %

47.1 % + 52.9 % = 100 %

Answer from: Quest

i think its 5049.

i hope this !

Answer from: Quest

A.(nh4)(2co3)is the correct answer

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What is the percent composition of the compound formed when 2.70 g of aluminum combines with oxygen...

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