Complete the following precipitation reaction with balanced molecular, total ionic, and net ionic equations. Remember to include the proper physical states and charges of ions. When writing ions, if a charge number is no "1", place the charge number before the charge sign. If a charge number is "1", do not include the chare number in the formula.
Na2S(aq) + ZnSO4(aq)>
molecular:
Total ionic: Reactants

Products
>
Net ionic:

Molecular: Na₂S (aq) + ZnSO₄ (aq) → ZnS (s) ↓ + Na₂SO₄(aq)

Total ionic: Reactants

2Na⁺ + S⁻² (aq) + Zn²⁺ + SO₄⁻² (aq)

Products

2Na⁺ + SO₄⁻²(aq)

Net ionic: S⁻² (aq) + Zn²⁺(aq) → ZnS (s)

Explanation:

We determine the main reaction:

Na2S(aq) + ZnSO4(aq)>

The balanced molecular:

Na₂S (aq) + ZnSO₄ (aq) → ZnS (s) ↓ + Na₂SO₄(aq)

We determine the ions of each reactant and product:

2Na⁺ + S⁻² (aq) + Zn²⁺ + SO₄⁻² (aq) → ZnS (s) + 2Na⁺ + SO₄⁻²(aq)

As ths zinc suflide is a solid, we do not have to write their ions

Spectators ions are Na and sulfate

Net ionic: S⁻² (aq) + Zn²⁺(aq) → ZnS (s)

the answer would be a

1 is the answer to this problem