At a certain temperature, the K p for the decomposition of H 2 S is 0.859 . H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g ) Initially, only H 2 S is present at a pressure of 0.245 atm in a closed container. What is the total pressure in the container at equilibrium?

P = 0.444 atm

Explanation:

The reaction of decomposition of H₂S is:

                    H₂S(g)   ⇄  H₂(g)  + S(g)      

Initial            0.245          0           0

Equilibrium  0.245-x       x            x

The equilibrium constant (Kp) of the above reaction is the following:

    (1)

Knowing that initally, only H₂S is present at P = 0.245, the Kp of equation (1) at equilibrium is:

Using the quadratic formula we get x₁ = 0.199 and x₂ = -1.058.

Taking only the possitive number we have that:

Therefore, the total pressure in the container at equilibrium is:

I hope it helps you!

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

acid rain does not usually kill trees directly. instead, it is more likely to weaken the trees by damaging their leaves, limiting the nutrients available to them, or poisoning them with toxic substances slowly released from the soil. the main atmospheric pollutants that affect trees are nitrates and sulphates.