Be sure to answer all parts. In the electrolysis of molten BaI2, (a) What product forms at the negative electrode? (b) What product forms at the positive electrode? You do not need to include the states of matter in your answer.

(a) Barium is produced at the negative electrode

(b) Iodine is produced at the positive electrode

Explanation:

When  an electric current is passed through a solution containing electrolyte, a non spontaneous reaction is stimulated. This results in the flow of positively charged ions to negatively charged electrodes(cathode) and negatively charged ions to positively charged electrodes(anode)

When an electric current is passed through molten in the electrolytic cell, the following reactions takes place:

                                            → + 2

At the anode;

Iodine ions will lose an electron and will be oxidized to iodine

→ +

At  the cathode;

Barium ions gains electrons and its reduced to barium metal

+ → Ba

the answer is b. dilution

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3