If 5.05 g of ca(oh)2 and 6.70 g of h3po4 are available, how many moles of ca3(po4)2 will you produce from each?

a) 0.023 mol Ca3(PO4)2 from 5.05 g Ca(OH)2

b) 0.034 mol Ca3(PO4)2 from 6.70 g H3PO4

Explanation:

∴ Mw Ca(OH)2 = 74.093 g/mol

∴ Mw H3PO4 = 97.994 g/mol

a) n Ca3(PO4)2 = (5.05 g Ca(OH)2)×(mol Ca(OH)2/74.093 g)×(mol Ca3(PO4)2/3 mol Ca(OH)2) = 0.023 mol Ca3(PO4)2

b) n Ca3(PO4)2 = (6.70 g H3PO4)×(mol H3PO4/97.994 g)×(mol Ca3(PO4)2/2 mol H3PO4) = 0.034 mol Ca3(PO4)2

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.