Chemistry, 25.02.2020 03:38 kimberlylove387
F a temperature increase from "18.0 ∘C to 37.0 ∘C" triples the rate constant for a reaction, what is the value of the activation barrier for the reaction?
Answers: 2
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](/tpl/images/0522/6607/6d953.png)
= rate constant at 
= k
= rate constant at 
= 3k
= activation energy for the reaction = ?
= initial temperature = 
= final temperature = 
![\log (\frac{3k}{k})=\frac{Ea}{2.303\times 8.314 J/mol K}[\frac{1}{291 K}-\frac{1}{310 K}]](/tpl/images/0522/6607/6a456.png)
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F a temperature increase from "18.0 ∘C to 37.0 ∘C" triples the rate constant for a reaction, what is...
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