What is the diameter of a hemisphere with a volume of 85962 ft^3, to the nearest tenth of a foot?

D= 69.0

Step-by-step explanation: Recall that the volume of a sphere is V = (4/3)πr^3

A hemisphere is half of a sphere, so the volume of a hemisphere is V = (1/2)(4/3)πr^3 or V = (2/3)πr^3

Now we can plug in the volume given to us by the problem to solve for the radius r

V = (2/3)πr^3

85962 = (2/3)πr^3

Use your calculator to multiply by 3, divide by 2π, and take the cube root to find r.

r ≈ 34.4947

The diameter is twice the radius, so

d ≈ 69.0

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: