If the molten nacl is replace dby an 1.0m aqueous sodium chloride solution how much sodium can be collected if a curret of 1.0 a is applied for 1.0 hour?

0.89 g

Explanation:

The knowledge of Faraday's second law of electrolysis is generally required here; the law states that when the same quantity of electricity is passed through a solution of different electrolyte, the mass of the substance deposited is directly proportional to it's chemical equivalence.

NOTE: 1 Farads  (F) = 96,500 Coloumbs (C)

What this law means is that,

Generally, the quantity of electricity required to displace potassium (K) from a compound is 96500C because the charge of K is 1+ while the quantity of electricity required to displace calcium (Ca) from a solution is 2 x 96500 because the charge of Ca is 2+.

To the question,

the quantity of electricity required to displace 23g (atomic mass of sodium) of sodium from a solution is 96,500 C because the charge of sodium is 1+. However, when a current of 1A is applied to a solution containing sodium for one hour, the quantity of electricity that passes through the solution is

Q = It  (Faraday's first law of electrolysis)

I = current

t = time in secs hence 1 hour = 1 x 60 x 60 = 3,600 s

Q = 1 x 3,600 =3,600 C

Hence, if 96,500 C will displace 23 g of sodium

3, 600 C will displace ??

From the above,

?? = 23 x 3,600/96,500

?? = 0.89 g

3,600 C will displace 0.89g of sodium (which can hence be collected)

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but