Ared light source emits light of a certain frequency. a violet light source emits light that has double the frequency of the red light source. how does the wavelength of the red light compare to the violet light.

The wavelength of red light is double the wavelength of violet light.

Let = Frequency of red light source

Let = Frequency of violet light source

Let λR = Wavelength of red light source

Let λV = Wavelength of violet light source

Given: Frequency of violet light is two times (double) the frequency of red light.

Therefore ........................(1)

The relation between speed of light (c), frequency (n) and wavelength (λ) is given by

c = nλ

Frequency is inversely proportional to λ.

The speed of light remains constant for both light sources = c = 3 × 10⁸ m/s²

For red light source: λR  ........................(2)

For violet light source: λV ..................(3)

Equating (2) and (3), we get

λR = λV

From (1)

λR = λV

λR = 2 × λV

Therefore, wavelength of red light is two times the wavelength of violet light.

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.