Note: pm is ”picometer” or 1 x 10-12 m.

calculate the answer in units of g/cm3.

calculate the average density of a single

atom by assuming that it is a uniform sphere

of radius 135.9 pm and its mass is 5.71 ×

10^−22 g. the volume of a sphere is 4

3

π r3

.

answer in units of g/cm3

.

d = 54.4 g/cm³

Explanation:

Given data:

Radius of sphere = 135.9 pm

Mass = 5.71 ×10⁻²² g

Volume = 4/3 ×πr³

Density = ?

Solution:

Volume = 4/3 ×πr³

Volume = 4/3×3.14× (135.9×10⁻¹²m)³

Volume = 4.2 × (135.9×10⁻¹²m)³

Volume = 1.05 ×10⁻²⁹m³

Volume = 1.05 ×10⁻²⁹×10⁶ cm³

Volume = 1.05 ×10⁻²³cm³

Density:

d = m/v

d =  5.71 ×10⁻²² g/1.05 ×10⁻²³cm³

d = 54.4 g/cm³

in theory, limestone is composed principally of the compound calcium carbonate - caco3, but in reality this compound is deposited in conditions involving a number of other compounds as impurities so it ends up being a mixture of many compounds.

hope this : -)

tony (lordcaos066)