Find the center, vertices, and foci of the ellipse with equation x squared divided by 36 plus y squared divided by 100 = 1. a. Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (0, -8), (0, 8)
b. Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (0, -6), (0, 6)
c. Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-8, 0), (8, 0)
d. Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (-6, 0), (6, 0)

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

the one below it is a function

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²