subject
Chemistry, 17.11.2019 21:31 Aminton737

Nitrogen monoxide can be produced from the reaction of ammonia and oxygen according to the reaction below:
4 nh3 (g)+ 5 o2 (g) → 4 no (g) + 6 h2o (l)
a) what do the coefficients in the above balanced equation represent?
b) what are the conditions needed in order to solve a stoichiometric problem involving gaseous reactants and products?
c) calculate the mass of no and h2o produced when 5.60 l of o2 reacts at stp according to the reaction below.
answer questions a – c.

ansver
Answers: 1

Another question on Chemistry

question
Chemistry, 22.06.2019 09:00
Identify the electromagnets with poles that are reversed from the electromagnet shown above
Answers: 3
question
Chemistry, 22.06.2019 12:00
What are the first two quantum numbers for the electrons located in subshell 4d? what are the first three quantum numbers for the electrons located in subshell 2s? how many electrons can be held in a sublevel l = 3? how many electrons can be held in the energy level n = 4? how many electrons in an atom can share the quantum numbers n = 4 and l = 3?
Answers: 1
question
Chemistry, 22.06.2019 15:00
Which of the following is the correct formula for copper (i) sulfate trihydrate? cuso4 · 3h2o cuso4(h2o)3 cu2so4(h2o)3 cu2so4 · 3h2o
Answers: 1
question
Chemistry, 22.06.2019 17:10
Acalorimeter is to be calibrated: 51.203 g of water at 55.2 degree c is added to a calorimeter containing 49.783 g of water at 23.5c. after stirring and waiting for the system to equilibrate, the final temperature reached is 37.6 degree c. specific heat capacity of water (s = 4.18 j/g∙degree c). calculate the calorimeter constant. (smδt)warm water = -[(smδt)cold water + (calorimeterδtcold water)]
Answers: 2
You know the right answer?
Nitrogen monoxide can be produced from the reaction of ammonia and oxygen according to the reaction...
Questions
question
Mathematics, 18.08.2020 18:01
question
History, 18.08.2020 18:01
question
Mathematics, 18.08.2020 18:01
question
Mathematics, 18.08.2020 18:01
Questions on the website: 13722367