Aproton and an electron in a hydrogen atom are separated on the average by about 5.3 × 10−11 m. what is the magnitude of the electric field set up by the proton at the location of the electron? the value of the coulomb constant is 8.99 × 109 n · m2/c2. answer in units of n/c

5.10¹¹ N/C

Explanation:

As we have a proton and a neutron, we can consider that they both have the same charge, this is:

e- = e+ = |1,6x10⁻¹⁹ C| , this number is in absolute value

Then, the formula needed to calculate the magnitude of the electric field from a charged particle is:

E= kqQ/r²

Where:

K= Coulomb constant

Q= charge  

r = distance between two charges

Then:  

E= 8.99x10⁹N/C²*(1.6x10⁻¹⁹C)/(5.3x10⁻¹¹m)²

E=5.12x1011 N/C

It is important that this value is a magnitude, it does not have any sign (positive or negative), for the magnetic field

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

your mom.com . : 0000