Carbonyl fluoride, cof2, is an important intermediate used in the production of fluorine-containing compounds. for instance, it is used to make the refrigerant carbon tetrafluoride, cf4 via the reaction 2cof2(g)⇌co2(g)+cf4(g), k=7.80 at 850 k if only cof2 is present initially at a pressure of 240 kpa, what is the partial pressure of cof2 at equilibrium? you can convert the units of pressure from kpa to bar, using the relation 1 kpa=0.01 bar.

pCOF₂ = 101.8 kPa = 1.018 bar

Explanation:

What we need is to determine the equilibrium pressure for COF₂ .

Now the equilibrum is

                           2COF2(g)⇌   CO2(g)+  CF4(g)  with Kp = 7.80

initially kPa          240                 0               0

react                      -2x                + x            + x

equilibrium        240-2x              +x            +x

Kp = pCO₂ x pCF₄ / p COF₂

7.80 = x² /( 240-2x )²

taking square roots to both sides of the equation

√7.80 = √(x² /( 240-2x )²)

2.8 = x / ( 240 - 2x )

672 - 5.6x = x

672 = 6.6x

672//6.6 = x = 101.8

pCOF₂ = 101.8 kPa = 1.018 bar

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.