Astudent reacted nis2 (mm = 122.83 g/mol) with o2 (mm=32.00 g/mol) to make so2 (mm=64.07 g/mol) according to this balanced equation
2nis2+5o2=2nio+4so2
if the actual amount of so2 made were (4.3090x10^2) g ehen the theoretical yield was (8.78x10^2) g what was the percent yield?
enter in scientific notation

Percentage yield = 0.49 × 10² %

Explanation:

Given data:

Actual yield of SO₂ = 4.309 ×10² g

Theoretical yield of SO₂ = 8.78 ×10² g

Percentage yield = ?

Solution:

Chemical equation:

2NiS₂ + 5O₂ → 2NiO + 4SO₂

Percentage yield:

Percentage yield = actual yield / theoretical yield × 100

Percentage yield = 4.309 ×10² g  / 8.78 ×10² g  × 100

Percentage yield = 0.491 × 100

Percentage yield = 49.1%

In scientific notation:

Percentage yield = 0.49 × 10² %

20 drops hope this