What is the change in heat energy when 114.32g of water at 14.85oc is raised to 18.00oc?

Given:

114.32g of water

14.85oC is raised to 18.00oC

Required:

Change in heat energy

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

The specific heat of the water is 4.18 J/g-K

Plugging in the values into the equation

H = mCpT

H = (114.32g) (4.18 J/g °C) (18 – 14.85)

H = 1,505.3 J

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