6. write the ice chart for the reaction of 32.0 g of sulfur and 71.0 g of chlorine: s8 + 4 cl24s2cl2 after completing the chart give a. the mass of product b. the mass of agent in excess c. the mass produced if there is an 87.% yield

ICE Table Figure

a. 67.37 g

b. 35.62 g

c. 58.61 g

Explanation:

For the ICE table we have to keep in mind that we have 4 moles of and 1 mol of and the reactives are consumed, so for we will have -4X and for we will have -X. Follow the same logic we will have -4X for .

a. Mass of the product

Molar mass of = 256.52 g/mol

Molar mass of =70.9 g/mol

Molar mass of =135.03 g/mol

We have to find the limiting reagent in the reaction:

Divide by the coefficients in the balanced reaction:

The limiting reagent would be

Now is posible to calculate the amount of produced:

b. Mass  in excess

C. 87%Yield

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b