Assume that you have 1, 2, 5, and 10 ml pipets and a 25 ml volumetric flask only. describe in detail how you would prepare a solution with a concentration near 0.100 m from a 0.650 m stock solution using the glassware listed above. calculate the final concentration of the diluted solution (it won't be exactly 0.100 m). it should be within 10% of 0.100 m. ( see the lab skills for the accuracy on volumetric pipets and flasks.)

Explanation:

The given data is as follows.

      = 25 ml,           = 0.10 M

      = x ml = ,         = 0.650 M

It is known that relation between molarity and volume of two solutions is as follows.

        =

        =

                x = 0.00385 L

or,                = 3.85 ml

Since, this volume is closest to 4 ml so, we have to use a 2 ml pipette two times and then we have to put it in a 25 ml volumetric flask.

Hence, calculate the overall concentration as follows.

                    =

                      =    

                        x = 0.104 M

Therefore, it is about 3.8% error that is lower than the required error.

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: