A truck engine slows down from 3700 rpm to 1800 rpm in 4.25 s. How many revolutions were made by the engine during this time

194.81 revolutions

Explanation:

Given that,

Initial angular velocity,

Final angular velocity,

Time, t = 4.25 seconds

We need to find the number of revolutions occur during this time.

3700 rpm = 387.46 rad/s

1800 rpm = 188.49 rad/s

Let is angular acceleration. Using first equation to find it.

Now let us suppose that the number of revolutions are .

or

Hence, there are 194.81 revolutions.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

a.   mass number from atomic number