Consider the reaction: 2 hi(g) ⇄ h2(g) + i2(g) it is found that, when equilibrium is reached at a certain temperature, hi is 35.4 percent dissociated. calculate the equilibrium constant kc for the reaction at this temperature.

Kc = 0,075

Explanation:

For a reaction:

A + B ⇄ xC + yD

Kc =

For the reaction:

2 HI(g) ⇄ H₂(g) + I₂(g)

Kc = (1)

In equilibrium:

[HI] = 1- 2x

[I₂] = x [H₂] = x

If 35,4% is dissociated:

[HI] = 1-2x = 0,646 ⇒ x = 0,177

[I₂] = 0,177 [H₂] = 0,177

Replacing in (1):

Kc =

kc = 0,075

I hope it helps!

the product of the pressure and volume is also constant