Combining 0.301 mol fe2o3
with excess carbon produced 11.6 g fe.

fe2o3+3c⟶2fe+3co

what is the actual yield of iron in moles?

The actual yield of iron (Fe) in moles is 0.207 mol.

Why?

Since we know the chemical equation, and how much Fe is produced,  we can calculate the actual yield of iron in moles using the following equation:

From the statement, we know that there are 11.6 g of Fe.

We also know the molar mass of the Fe which is:

Now, calculating we have:

Hence, we have that the actual yield of iron (Fe) in moles is 0.207 mol.

Have a nice day!

The actual yield of iron in moles is 34.5%

Explanation:

The balanced chemical equation is

The conversions are moles to moles Fe and  moles Fe to mass Fe  

Mole ratio of is 1 : 2

So using mole ratio we see

=0.601 mol Fe is produced.

By multiplying with molar mass of Fe we can convert moles Fe to mass Fe.

That is  

Mass Fe = moles Fe × molar mass Fe

=33.566 g Fe produced.

(Theoretical yield)

11.6 g given is the actual yield.

% yield=(actual yield )/(Theoretical yield )×100%

= 34.5% is the Answer