State which theorem you can use to show that the quadrilateral is a parallelogram.

We can use the theorem ''Parallelogram Diagonals Converse'' to show that the quadrilateral is a parallelogram.

Step-by-step explanation:

We know that the diagonals of any parallelogram bisect each other, each diagonal cutting the other into two equal parts.

In other words, according to Parallelogram Diagonals Theorem Converse, the figure will be a parallelogram if the diagonals of the quadrilateral figure cut (bisect) each other. It is basically the

From the given Parallelogram, it is clear that the diagonals bisect each other, each diagonal cutting the other into two equal parts with the length 3 units.

Therefore, we can use the theorem ''Parallelogram Diagonals Converse'' to show that the quadrilateral is a parallelogram.

what's the question?

step-by-step explanation:

there is no question.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58