If the reaction produced 15.5 g co2, how many grams of heptane were burned?

5 g of heptane were burned.

Explanation:

Given data:

Mass of CO₂ produced = 15.5 g

Mass of heptane burned = ?

Solution:

Balance chemical equation:

C₇H₁₆ + 11O₂ →7CO₂ + 8H₂O

First of all we will calculate the moles of CO₂ produced.

Number of moles = mass / molar mass

Molar of CO₂ = 44 g/mol

Number of moles = 15.5 g / 44 g/mol

Number of moles = 0.3523 mol

Now we will compare the moles of CO₂ and C₇H₁₆ from balance chemical equation

                     CO₂      :     C₇H₁₆

                      7         :        1

                 0.3523     :        1/7 × 0.3523 = 0.05 mol

Mass of C₇H₁₆:

Number of moles = mass / molar mass

Mass = number of moles ×  molar mass

Mass =  0.05 mol / 100 g/mol

Mass = 5 g

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

the answers would be

the first one and the second one