Aluminum chloride is named as if it is ionic but it is really molecular, with the formula al2cl6. it can be formed by direct reaction of the elements. 2al(s) + 3cl2(g) → aicia) if 0.824 g of aluminum react with excess chlorine, how many grams of aluminum chloride can be obtained? (4.07 g) calculate the grams of chlorine that react with 0.194 g of aluminum. (0.765 g) 1.2.b

1) 4.0744 grams of aluminum chloride can be obtained.

2) 0.7652 grams of chlorine that react with 0.194 g of aluminum.

Explanation:

1) Moles of aluminum  :

According to reaction, 2 moles of aluminum gives 2 moles of aluminium chloride.

Then 0.03052 mol of aluminum will give with :

of aluminium chloride.

Mass of 0.03052 moles of aluminium chloride :

4.0744 grams of aluminum chloride can be obtained.

2) Moles of Aluminium :

According to reaction, 2  moles of aluminum reacts with 3 moles of chlorine gas.

Then 0.007185 mol of aluminum will react with:

of chlorine gas.

Mass of 0.01077 mol  moles of chlorine gas:

0.7652 grams of chlorine that react with 0.194 g of aluminum.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

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