Aconical container can hold 120π cubic centimeters of water. the diameter of the base of the container is 12 centimeters.

the height of the container centimeters. if its diameter and height were both doubled, the container's capacity would times its original capacity.

Cone volume=(1/3)hpir^2
d/2=r
d=12
d/2=12/2=6=r

V=120pi
120pi=(1/3)hpi6^2
120pi=(1/3)hpi36
120pi=12hpi
divide both sides by pi
120=12h
divide 12
10=h cm

if height and diameter is doubled aka height and radius are doubled

V=(1/3)(2h)pi(2r^2)
we want to see how it compares to V=(1/3)hpir^2

V=(1/3)(2h)pi(2r^2)
V=2(1/3)(h)pi4r^2
V=8((1/3)hpir^2)
the volume is increased by 8 times

blanks are
10
8

The answer for this question is 80