Calculate δh⁰298 (in kj) for the process p(s) + 5/2 cl2(g) → pcl5(g) from the following information.
p(s) + 3/2 cl2(g) → pcl3(g) δh⁰298 = −287 kj
pcl3(g) + cl2(g) → pcl5(g) δh⁰298 = −88 kj

for the process is -375 kJ

Explanation:

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hloride, what is the mass of calcium in

explanation:

58750.08068 is the answer i think