Someone help me with this

find points a b c

<a=32

<b=40

<c=40

Step-by-step explanation:

to find angle a you have to subtract the 50 minus 180 to find the angle close to the 50 because angles in a straight line add up to 180. the answer will be

180-50=130

after finding the angle in that triangle you must add it to the other angle present which is 18° then subtract by 180 because angles in a straight line add up to 180

130+18+a=180

a=180-148

a=32 and that's how you find a

to find b you must know that the angle at the center is twice the angle at the circumference meaning the large angle C is 90°,now if it's 90° inorder to find the big angle B you must add the 18+90 then subtract 180

18+90+B=180

B=180-108

=72

since the combination of angle a and b will give you 72 you can find angle c by subtracting a from 72

c=72-32

=40

then if you look at angle c and angle b you can tell that they are alternating meaning angle b is also 40

I hope this helps

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

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