Calculate the equilibrium constant kc at 25 c from the free - energy change for the following reaction . zn(s) + 2ag+(aq)< > zn2+(aq)+ ag(s)

Explanation: For the given reaction:

Concentrations of the ions are not given so we need to think about another way to calculate Kc.

We can calculate the free energy change using the standard cell potential as:

can be calculated using standard reduction potentials.

Standard reduction potential for zinc is -0.76 V and for silver, it is +0.78 V.

=

Reduction takes place at anode and oxidation at cathode. As silver is reduced, it is cathode. Zinc is oxidized and so it is anode.

 = 0.78 V - (-0.76 V)

 = 0.78 V + 0.76 V

 = 1.54 V

Value of n is two as two moles of electrons are transferred in the cell reaction F is Faraday constant and its value is 96485 C/mol of electron .

= -297173.8 J

Now we can calculate Kc using the formula:

T = 25+273 = 298 K

R =

--297173.8 = -(8.314*298)lnKc

297173.8 = 2477.572*lnKc

lnKc = 119.946

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.