Octane (c8h18) is a component of gasoline. complete combustion of octane yields h2o and co2. incomplete combustion produces h2o and co, which not only reduces the efficiency of the engine using the fuel but is also toxic. in a certain test run, 1.000 gallon (gal) of octane is burned in an engine. the total mass of co, co2, and h2o produced is 11.53 kg. calculate the efficiency of the process; that is, calculate the fraction of octane converted to co2. the density of octane is 2.650 kg/gal.

of octane had been converted to carbon dioxide CO₂.

Octane has a molar mass of

1.000 gallon of this fuel would have a mass of 2.650 kilograms or , which corresponds to of octane.

Octane undergoes complete combustion to produce carbon dioxide and water by the following equation:

An incomplete combustion of octane that gives rise to carbon monoxide and water but no carbon dioxide would consume not as much oxygen:

The mass of the product mixture is heavier than that of the octane supplied. Thus of oxygen were consumed in the combustion. There are of oxygen molecules in of oxygen.

Let the number of moles of octane that had undergone complete combustion as seen in the first equation be (). The number of moles of octane that had undergone incomplete combustion through the second equation would thus equal .

25 moles of oxygen gas is consumed for every two moles of octane that had undergone complete combustion and 17 moles if the combustion is incomplete.

Therefore out of the 23.2 moles of octane had undergone complete combustion to produce carbon dioxide.

the answer is true. hope it .

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2