Air at 7s°f and14.6 though a cfm(cubic ft per minute) and the the flow rate is 48000 psia flows though a rectangular duct of ix2 ft cross section. a hydraulic ughness factor for the duct, is 0.00015 ft. determine: raulic radius; and equivalent diameter b. velocity of flow c. reynolds number d. pressure drop per 100 ft of flow i nine line of constant diameter of

Explanation:

The given data is as follows.

Air is at and 14.6 psia.

= 0.00015 ft,     Flow rate, (Q) = 48000

(a)  Formula to calculate hydraulic radius is as follows.

                          =

                          = ft

Formula for equivalent diameter is as follows.

                                    =  

                                    = ft

(b)    Formula for velocity floe is as follows.

                         Q = VA

                     V =

                        = ft/min

                        = 24000 ft/min

(c)   Formula to calculate Reynold's number is as follows.

          =

                   =  (as and = 0.0443 lb/ft. hr)

                   = 53742.66 hr/min  

As 1 hr = 10 min. So,

                            = 3224559.6

(d)   Formula to calculate pressure drop is as follows.

Putting the given values into the above formula as follows.

                      =

                      = 6.238

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3