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35.
which of the following is not favourable for the formation of so3?
2s02(g) +o2(g) = 2so3(g); ah=-188 kj
a) high pressure. b) high temperature c) decreasing (so3]
d) increasing (so2]

b is the right answer of the following terms

The correct option is b

Explanation:

During chemical equilibrium, when ΔH is positive, this means the forward reaction is an endothermic reaction but when ΔH is negative, this means the forward reaction is an exothermic reaction. An increase in temperature have different effects on these types of reaction.

An increase in temperature when ΔH is negative causes the equilibrium to shift backward causing more reactants to be formed and when ΔH is positive, an increase in temperature causes more products to be formed.  

The question shows the ΔH of the reaction is -188 KJ hence the forward reaction is an exothermic reaction and an increase in temperature (High temperature) will favour the formation of more reactants and not favour the formation of the product SO₃.

NOTE: An increase in pressure (since the reactants are both gases), removal of product as it is formed (decreasing SO₃) and increasing the concentration of the reactant(s) (increasing SO₂) all favour the forward reaction hence will lead to the formation of more product (SO₃).

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.