You decide to establish a new temperature scale on which the melting point of ammonia (-77.75 ∘c) is 0∘a, and the boiling point of ammonia (-33.35∘c) is 100 ∘a. part a what would be the boiling point of water in ∘a?

The boiling point of water is

Explanation:

To convert the units of temperature, we use the equation:

where,

X = temperature in

Y = temperature in

LFP = lower fixed point

UFP = upper fixed point

LFP of is 0°A

UFP of is 100°A

LFP of is -77.75°A

UFP of is -33.35°A

Normal boiling point of water =

Putting values in above equation, we get:

Hence, the boiling point of water is

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2