When 1.0g of diethyl ether is converted to vapor at its boiling point, about how much heat is absorbed? (c4h10o, hvap= 15.7kj/mol, boiling point: 34.6°c)a) 2 jb) 2 kjc) 0.2 jd) 0.2 kj( show how you got the answer.)

Option D = 0.2 Kj

Explanation:

Given data:

Mass of diethyl ether = 1.0 g

Hvap = 15.7 Kj / mol

Heat absorbed = ?

Solution:

Q = mass ×  Hvap /  molar mass

Q = 1.0 g × 15.7 Kj / mol / 74.12 g/mol

Q = 15.7 Kj / 74.12

Q =  0.212 KJ

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