Aluminum reacts with 42 g of iron(ii) sulfate. how many grams of iron are formed? aluminum sulfate is the other product?

= 15.44 g

Explanation:

The equation for the reaction;

2Al+3 FeSO4 → Al(2)(SO4)(3)+3Fe

We can find;

Moles of iron (ii) sulfate = 42 g/ 151.908 g/mol

                                       = 0.2765 moles

Mole ratio of iron (ii) sulfate : Iron = 3 : 3 = 1 : 1

Therefore;

Moles of Iron produced = 0.2765 moles

Mass of iron = 0.2765 moles × 55.845 g/mol

                     = 15.44 g

it is important to conserve water because there is very limited amount of freshwater here on earth and if we are not smart about how we use it we will only be runnning out of our supply faster than neccessarry.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.