Write the pressure equilibrium constant expression for this reaction. 2co2 (g) + 4h2o (g) → 2ch3oh (l) + 3o2 (g)

The pressure equilibrium constant (Kp) = (P O₂)³/(P CO₂)²(P H₂O)⁴.

Explanation:

2CO₂ (g) + 4H₂O (g) → 2CH₃OH (l) + 3O₂ (g).

The pressure equilibrium constant (Kp) = the product of the pressure of the products side components / the product of the pressure of the reactantss side components.

each one is raised to a power equal to its coefficient.

∴ The pressure equilibrium constant (Kp) = (P O₂)³/(P CO₂)²(P H₂O)⁴.

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i believe the answer is three water molecules