What mass of hcl, in grams, is required to react with 0.610 g of al(oh)3  ?

0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

Given mass of = 0.610 g

Molar mass of = 78 g/mol

Number of moles of = 0.0078 moles

The reaction between and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

By Stoichiometry,

1 mole of   reacts with 3 moles of HCl

So, 0.0078 moles of will react with = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

Mass of HCl required will be = 0.8541 grams

a plasma is a warm ionized gasoline consisting of approximately equal numbers of definitely charged ions and negatively charged electrons. the characteristics of plasmas are notably unique from the ones of ordinary neutral gases in order that plasmas are considered a awesome "fourth kingdom of remember."

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.