the minimum constant speed at which she can catch the train is 2.7 m/s
given:
acceleration = 0.6
time = 4.5 s
to find:
velocity = ?
formula used:
from 1st kinematic equation we get,
v = u + at
u = initial speed of train = 0 m/s
v = final speed of the train
a = acceleration of the train
t = time
solution:
from 1st kinematic equation we get,
v = u + at
u = initial speed of train = 0 m/s
v = final speed of the train
a = acceleration of the train
t = time
v = 0 + (0.6 × 4.5)
v = 2.7 m/s
the minimum constant speed at which she can catch the train is 2.7 m/s