What is the temperature (°c) of 2.48 moles of gas stored in a 30.0 l container at 1559 mm hg? (r= 0.0821 l atm/ mol k)?

Answer is: the temperature is 28.9°C.

n = 2.48; amount of the gas.

V = 30.0 L; volume of the gas.

p = 1559 mmHg ÷ 760 mmHg/atm.

p = 2.05 atm; pressure of the gas.

R = 0.0821 L·atm/mol·K.

Ideal gas law: p·V = n·R·T.

T = p·V ÷ (n·R).

T = 302.05 K - 273.15.

T = 28.9°C; temperature of the gas.

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation:

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).