When entering coefficients to balance equations, recall that just writing the symbol implies "1." therefore, if a coefficient of "1" is required, choose "blank" for that box. balance the following reaction. mgcl2 + agno3 → agcl + mg(no3)2

The balanced equation is MgCl₂ +2AgNO₃ ⟶ 2AgCl + Mg(NO₃)₂

Step 1. Start with the most complicated-looking formula [Mg(NO₃)₂].

Put a 1 in front of it and balance its atoms.

MgCl₂ +AgNO₃ ⟶ AgCl + 1Mg(NO₃)₂

Step 2. Balance Mg.

1MgCl₂ +AgNO₃ ⟶ AgCl + 1Mg(NO₃)₂

Already balanced —1 atom each side.

Step 3. Balance N.

We have 2 N on the right-hand side and 1 N on the left. We need 2 N on the left. Put a 2 in front of AgNO₃.

1MgCl₂ +2AgNO₃ ⟶ AgCl + 1Mg(NO₃)₂

Step 4: Balance O

Done. We have 6 O on the left and 6 O on the right.

Step 5. Balance Ag.

We have 2 Ag on the left, so we need 2 Ag on the right. Put a 2 in front of AgCl.

1MgCl₂ +2AgNO₃ ⟶ 2AgCl + 1Mg(NO₃)₂

The balanced equation is

MgCl₂ +2AgNO₃ ⟶ 2AgCl + Mg(NO₃)₂

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2