The point A (3, 4) is reflected over the line x = 2, and then is reflected over the line x = -4. What are the coordinates of A'? (9, 4)
(-9, 4)
(1, 4)
(1, 2)

9514 1404 393

  (-9, 4)

Step-by-step explanation:

Reflection over the line x=a performs the transformation ...

  (x, y) ⇒ (2a -x, y)

So, reflection over the two lines will give the transformation ...

  (x, y) ⇒ (2·2 -x, y) = (4 -x, y) . . . . . reflection over x=2

then ...

  (4 -x, y) ⇒ (2(-4)-(4-x), y) = (x -12, y) . . . followed by reflection over x=-4

__

Reflecting (3, 4) over the two lines gives an image point of ...

  (x, y) ⇒ (x -12, y)

  (3, 4) ⇒ (3 -12, 4) = (-9, 4)

The coordinates of A' are (-9, 4).

Comment on double reflection

Reflection over the two lines results in a translation that is double the distance between the two lines. The translation is in the direction that the second line is from the first. Here, the lines are 2 -(-4) = 6 units apart, with the second line being to the left of the first. The translation is 12 units to the left.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high