What volume of 0.305 m agno3 is required to react exactly with 155.0 ml of 0.274 m na2so4 solution? hint: you will want to write a balanced reaction?

The balanced chemical equation for reaction of and is as follows:

From the balanced chemical equation, 2 mol of reacts with 1 mol of  .

First calculating number of moles of as follows:

On rearranging,

Here, M is molarity and V is volume. The molarity of  is given 0.274 M or mol/L and volume 155 mL, putting the values,

Since, 1 mol of  reacts with 2 mol of   thus, number of moles of    will be .

Now, molarity of   is given 0.305 M or mol/L thus, volume can be calculated as follows:

Therefore, volume of   is 278.5 mL.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.