What mass of naoh is needed to precipitate the cd2+ ions from 35.0 ml of 0.530 m cd(no3)2 solution?

The reaction is given as:

Here, one mole of cadmium nitrate gives one mole of cadmium hydroxide.

Now,

number of moles =  (1)

Concentration = 0.530 M

Volume = 35.0 mL

Substitute the above values in formula (1):

number of moles =  (1 L =1000 mL)

=

From the reaction, two moles of sodium hydroxide is needed to give one mole of cadmium hydroxide.

Now,

number of moles of sodium hydroxide which is needed to give of cadmium hydroxide.

Number of moles of sodium hydroxide  =

=

Now, mass of sodium hydroxide is calculated by:

Mass of sodium hydroxide  =

=

=

Thus, mass of sodium hydroxide required is

the answer is the first option

explanation:

just googled it m8. not that hard

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