Calculate the mass, in grams, of a single tellurium atom (mte = 127.60 amu ).

The mass, in grams, of a single tellurium atom = 2,118. 10⁻²² grams

Inside the atom consists of a nucleus containing 3 elementary particles, namely protons and neutrons, while electrons move around the nucleus.

Protons are positively charged (+1), electrons are negatively charged (-1). and neutrons are uncharged (neutral)

While the mass of 1 proton is equal to the mass of 1 neutron, equal to 1 amu and the electron has a mass smaller than both.

Atomic mass is the average atomic mass of all its isotopes

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu

So the atomic mass obtained is the mass of the atom relative to the 12th carbon atom

An atomic mass unit = amu is a relative atomic mass of 1/12 the mass of an atom of carbon-12.

The 'amu' unit has now been replaced with a unit of 'u' only

The hydrogen atom is the lightest atom whose mass is 1.67 x 10⁻²⁷kg (measured using a mass spectrometer) and simplified to 1 amu (atomic mass unit).

1 amu = 1,66.10⁻²⁴ grams

For example the C-12 carbon atomic mass is 12 amu, C-13 is 13 amu

Single tellurium atoms have = 127.60 amu

So that the mass is in grams:

mass = 127.60 amu x 1.66.10⁻²⁴

mass = 2,118. 10⁻²² grams

atomic weight of 120.9038 amu

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element 2512X

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about subatomic particles statement

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Keywords: atomic mass, amu

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

c.

explanation: