Determine the enthalpy of solution for a solid with δh values as described in each scenario.

The branch of science that deals with chemicals and bonds are called chemistry. There are two types of solution and these are acidic and basic.

The correct answer is mentioned as described

The enthalpy of solution formation depends on how much heat is released or absorbed during the dissolution process. So it can be negative (exothermic) or positive (endothermic)

When the solid is dissolved into the solution, 3 stages of the process will occur:

If the enthalpy of stage 1 + 2 which is a bond-breaking enthalpy is greater than the enthalpy of stage 3 which is the bond-forming energy, the enthalpy of the solution will be endothermic (positive value,> 0), but vice versa if the enthalpy of stage 1 + 2 is smaller than the stage 3, the enthalpy of the solution will be exothermic (negative, <0)

And if stage 1 + 2, the enthalpy value is the same as stage 3, the enthalpy of the solution is 0, and it is said that this solution is ideal. From the above problem, we complete the picture that is asked according to the scenario

If we look at box 1, the value of ΔH of the solution will be positive because the enthalpy of the bond breaker is 3x greater than the enthalpy of the bond-forming, so the solution is endothermic

For box 2, the solution ΔH is 0 because the enthalpy values 1 + 2 and 3 are the same. As for box 3, ΔH solution will be negative (exothermic) because enthalpy 1 + 2 is less than 1/3 of enthalpy stage 3

Hence, the correct answer is mentioned above.

For more information about the enthalpy, refer to the link:-

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Box 1, the value of ΔH solution is positive (endothermic)

Box 2 ΔH value = 0 and ,

Box 3 ΔH the value of ΔH solution is negative (exothermic)

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The enthalpy of solution formation depends on how much heat is released or absorbed during the dissolution process. So it can be negative (exothermic) or positive (endothermic)

When the solid is dissolved into the solution, 3 stages of the process will occur:

        This enthalpy is endothermic, can be symbolized as ΔH1

If the enthalpy of stage 1 + 2 which is a bond-breaking enthalpy is greater than the enthalpy of stage 3 which is the bond-forming energy, the enthalpy of the solution will be endothermic (positive value,> 0), but vice versa if the enthalpy of stage 1 + 2 is smaller than the stage 3, the enthalpy of the solution will be exothermic (negative, <0)

And if stage 1 + 2, the enthalpy value is the same as stage 3, the enthalpy of the solution is 0, and it is said that this solution is ideal

From the above problem, we complete the picture that is asked according to the scenario

If we look at box 1, the value of ΔH of the solution will be positive because the enthalpy of the bond breaker is 3x greater than the enthalpy of the bond-forming, so the solution is endothermic

For box 2, the solution ΔH is 0 because the enthalpy values 1 + 2 and 3 are the same

As for box 3, ΔH solution will be negative (exothermic) because enthalpy 1 + 2 is less than 1/3 of enthalpy stage 3

an exothermic reaction

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as endothermic or exothermic

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an exothermic dissolving process

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Keywords: exothermic, endothermic, enthalpy

wher is the rest of the question